C-32 D-64 E-128 F-256 Apr 2026

So formula: Letter position a=1, b=2, c=3, etc. 3. Extending the Sequence Following the pattern:

Better: If we say c = 3rd letter of alphabet → number = 2^(3+2) = 2^5 = 32 (yes!) d = 4th letter → 2^(4+2) = 2^6 = 64 (yes!) e = 5th → 2^(5+2) = 128 (yes!) f = 6th → 2^(6+2) = 256 (yes!) c-32 d-64 e-128 f-256

But 32 in hex = 0x20, not “C” — so not direct hex. ASCII: 'c' = 99 decimal, 'd' = 100, 'e' = 101, 'f' = 102. No match to 32, 64, etc. (D) Exponential Growth Teaching Tool Most likely purpose: Letter = just an index (c=3rd letter → 2^(5)?? Let's check) So formula: Letter position a=1, b=2, c=3, etc

Next letter: g (7th letter) → 2^(7+2) = 2^9 = 512 h → 2^(8+2) = 1024 i → 2048 j → 4096 ASCII: 'c' = 99 decimal, 'd' = 100, 'e' = 101, 'f' = 102

Let’s map: a = 1st → 2^(a+4)? No.