ΔVout / Vout = (Rload * ΔIL) / (8 * L * fsw)

When it was time for his lab session, David was well-prepared. He and his lab partner, Rachel, worked together to build a buck converter and measure its performance. David applied the concepts he had learned that morning, carefully adjusting the circuit parameters to achieve the desired output voltage and ripple.

It was a typical Monday morning for David, a graduate student studying power electronics. He had a long day ahead of him, with a lecture on DC-DC converters and a lab session to follow. As he sipped his coffee, he opened his textbook, "Fundamentals of Power Electronics, 2nd Edition" by Erickson and Dragan, and began to review the chapter on converters.

As he worked through the problems, David encountered a challenging question: a buck converter with a input voltage of 12V, an output voltage of 5V, and a load resistance of 10 ohms. The question asked him to find the inductor value required to achieve a output voltage ripple of 1%. David wasn't sure where to start, but after re-reading the relevant section in the textbook, he remembered the formula for output voltage ripple:

where ΔVout is the output voltage ripple, Vout is the output voltage, Rload is the load resistance, ΔIL is the inductor current ripple, L is the inductance, and fsw is the switching frequency.