Principles Of Physics A Calculus-based Text 5th Edition Solution -
North component: 20.0 km + 35.0 km * cos(60.0°) = 20.0 km + 17.5 km = 37.5 km West component: -35.0 km * sin(60.0°) = -30.3 km
R = √(37.5 km)^2 + (-30.3 km)^2 = 48.2 km North component: 20
A car travels 20.0 km due north and then 35.0 km in a direction 60.0° west of north. Find the magnitude and direction of the car's resultant displacement. North component: 20
:
The force acting on the block is:
The acceleration of the block is 4.90 m/s^2. North component: 20
North component: 20.0 km + 35.0 km * cos(60.0°) = 20.0 km + 17.5 km = 37.5 km West component: -35.0 km * sin(60.0°) = -30.3 km
R = √(37.5 km)^2 + (-30.3 km)^2 = 48.2 km
A car travels 20.0 km due north and then 35.0 km in a direction 60.0° west of north. Find the magnitude and direction of the car's resultant displacement.
:
The force acting on the block is:
The acceleration of the block is 4.90 m/s^2.