Given kn2000 , might be in 2000 ? If kn = in, then k→i (-2), n→n (0) not consistent. Let’s check ly again: if ly = of (common): l (12) → o (15) = +3, y (25) → f (6) = 25+3=28 mod 26=2→b? No, that's wrong. Given the complexity, I suspect it's a Caesar shift of +5 (decrypt by -5):
b↔y r↔i n↔m a↔z m↔n j↔q → yimznq
Better: Let’s actually decode ly assuming l → i and y → n . l (12) to i (9) = -3 y (25) to n (14) = -11? That’s inconsistent unless it’s not a Caesar shift.
t↔g h↔s m↔n y↔b l↔o → gsnbo
If ciphertext letter → plaintext letter by shifting (Caesar cipher with key 3, decode by shifting left 3):
thmyl → guzly brnamj → oean zw no.
But note: kn2000 might mean the key is ? Or it's a citation? thmyl brnamj zf awrj ly alkybwrd kn2000
t(20)-5=15→p h(8)-5=3→d m(13)-5=8→i y(25)-5=20→u l(12)-5=7→h → pdiuh not English. because ly with shift -7: l(12)-7=5→f, y(25)-7=18→s → fs no. Given that this is taking too long, I'll guess the intended solution is a ROT13 cipher, giving:
But simpler: maybe but with kn2000 as hint: kn = xa in ROT13? kn in ROT13: k→x, n→a, so xa2000 . Not helpful. Step 10: Try ROT13 on kn2000 → xa2000 not meaningful.
a b c d e f g h i j k l m n o p q r s t u v w x y z d e f g h i j k l m n o p q r s t u v w x y z a b c (encryption: plain +3 = cipher) Given kn2000 , might be in 2000
t (20) → q (17)? That doesn't look right because thmyl would start with q . But maybe ly = in works.
That doesn't look right either. Given the format, it's more likely a or similar. But without quick success, the most plausible intended plaintext is something like: "useful paper: submit your work by November 2000" or "useful paper: final draft for review by 2000" But since I can't decode it in one go, I'd need more time or a known key.